FINDING STEEL GRADE

• Problem Description

  
  A certain grade of steel is graded according to the following conditions.
  
  Hardness must be greater than 50.
  Carbon content must be less than 0.7.
  Tensile strength must be greater than 5600.
  The grades are as follows:
  
  Grade is 10 if all three conditions are met.
  
  Grade is 9 if conditions (i) and (ii) are met.
  Grade is 8 if conditions (ii) and (iii) are met.
  Grade is 7 if conditions (i) and (iii) are met.
  Grade is 6 if only one condition is met.
  Grade is 5 if none of three conditions are met.
  Write a program, if the user gives values of hardness, carbon content and tensile strength of the steel under consideration and display the grade of the steel.

• CODING ARENA

• #include <stdio.h>

  int main()

  {

    long t=0,i=0,grade=0;

    long hs,ts;

    float cc;

    scanf("%lu",&t);

    for(i=0;i<t;i++)

    {

      scanf("%lu%f%lu",&hs,&cc,&ts);

      if(hs>=50&&cc<=0.7&&ts>=5600)

      {

        grade=10;

      }

      else if(hs>=50&&cc<=0.7)

      {

        grade=9;

      }

      else if(cc<=0&&ts>=5600)

      {

        grade=8;

      }

      else if(hs>=50&&ts>=5600)

      {

        grade=7;

      }

      else if (hs>=50||cc<=0.7||ts>=5600)

      {

        grade=6;

      }

      else

      {

        grade=5;

      }

    printf("Grade %lu\n",grade);

    }

    return 0;

  }

• Test Case 1

  
  Input (stdin)

  2
  
  53 0.7 5602
  
  55 0 5499
  
  

  Expected Output

  Grade 10
  
  Grade 9

• Test Case 2

  
  Input (stdin)

  5
  
  49 0.8 5599
  
  55 0.6 5602
  
  45 0 5601
  
  60 0.2 5700
  
  55 0.5 5500
  
  

  Expected Output

  Grade 5
  
  Grade 10
  
  Grade 8
  
  Grade 10
  
  Grade 9