STRUCTURE 33

• Problem Description

  
  Declare a structure fraction that has two fields numerator and denominator .Create two variables and and compare them using function. Return 0 if the two variable are equal ,-1 if the fraction is less than the second and 1 otherwise. You may convert a fraction into a floating point number for your convenience
  
  Input and Output Format:
  
  Refer sample input and output for formatting specification.
  
  All float values are displayed correct to 2 decimal places.
  
  All text in bold corresponds to input and the rest corresponds to output.

• CODING ARENA

• #include <stdio.h>

  struct fraction

  {

    int n,d;

  };

  int compare(struct fraction a,struct fraction b)

  {

    float val1=(float)(a.n)/(float)(a.d);

    float val2=(float)(b.n)/(float)(b.d);

    if(val1<val2)

      return -1;

    else if(val1==val2)

      return 0;

    else

      return 1;

  }

  int main()

  {

    struct fraction a,b;

    scanf("%d%d",&a.n,&a.d);

    scanf("%d%d",&b.n,&b.d);

    int val=compare(a,b);

    if(val==0)

      printf("%d/%d is equal to %d/%d",a.n,a.d,b.n,b.d);

    else if(val==-1)

      printf("%d/%d is smaller than %d/%d",a.n,a.d,b.n,b.d);

    else 

      printf("%d/%d is greater than %d/%d",a.n,a.d,b.n,b.d);

  
  

  return 0;

  }

• Test Case 1

  
  Input (stdin)

  12 12
  
  12 22
  
  

  Expected Output

  12/12 is greater than 12/22

• Test Case 2

  
  Input (stdin)

  23 44
  
  99 23
  
  

  Expected Output

  23/44 is smaller than 99/23