GRADING SYSTEM

• Problem Description

  
  " A certain grade of steel is graded according to the following conditions.
  Hardness must be greater than 50.
  Carbon content must be less than 0.7.
  Tensile strength must be greater than 5600.
  
  
  
  
  The grades are as follows:
  
  Grade is 10 if all three conditions are met.
  Grade is 9 if conditions (i) and (ii) are met.
  Grade is 8 if conditions (ii) and (iii) are met.
  Grade is 7 if conditions (i) and (iii) are met.
  Grade is 6 if only one condition is met.
  Grade is 5 if none of three conditions are met.
  
  
  
  Write a program, if the user gives values of hardness, carbon content and tensile strength of the steel under consideration and display the grade of the steel.
  Input
  
  The first line contains an integer T, total number of testcases. Then follow T lines, each line contains three numbers hardness, carbon content and tensile strength of the steel.
  Output
  
  Print Grade of the steel depending on Conditions.
  Constraints
  
  1 <= T <= 1000
  1<= hardness, carbon content, tensile strength <=10000
  
  "
  

• CODING ARENA::

• #include <stdio.h>

  int main()

  {

    int i,n,a,c;

    float b;

    scanf("%d",&n);

    for(i=0;i<n;i++)

    {

      scanf("%d\t%f\t%d",&a,&b,&c);

      if(a>50 && b<0.7 && c>5600)

        printf("\n10");

      else if(a>50 && b<0.7 && c<5600)

        printf("\n9");

      else if(a<50 && b<0.7 && c>5600)

        printf("\n8");

      else if(a>50 && b>0.7 && c>5600)

        printf("\n7");

      else if(a>50 || b<0.7 || c>5600)

        printf("\n6");

      else

        printf("\n5");

    }

        

  
  

  return 0;

  }

• Test Case 1

  
  Input (stdin)

  3
  
  53 0.6 5602
  
  45 0 4500
  
  0 0 0
  
  

  Expected Output

  10
  
  6
  
  6

• Test Case 2

  
  Input (stdin)

  2
  
  90 0.1 6000
  
  4 8 40
  
  

  Expected Output

  10
  
  5