• Problem Description

  
  ") A new Canteen is opened in IIST Campus. Since today is the opening day, the canteen owner is giving an offer, in which every student must purchase 5 items each each of cost <1,000. The offer is, student can pay any amount, but the amount paid is the result of four binary operations ( +, - , *, / ) between the cost of five items. Now your taks is to help the student save his money. NOTE: No binary operator is to be repeated.
  Input
  Input consists of five integers each seperated by spaces.
  Output
  Your output must contain an ineger satisfying the above conditions
  "
  

• CODING ARENA

• #include <stdio.h>

  int main()

  {

    int a[5],i,total;

    float sum=0,sub=0,mul=1,div=1;

    for(i=0;i<5;i++)

    {

      scanf("%d",&a[i]);

    }

    for(i=0;i<5;i++)

    {

      sum=sum+a[i];

    }

    for(i=0;i<5;i++)

    {

      sub=a[i]-sub;

    }

    for(i=0;i<5;i++)

    {

      mul=mul*a[i];

    }

    for(i=0;i<5;i++)

    {

      div=a[i]/div;

    }

    total=sum+sub+mul+div;

    if(total<1000)

    {

      printf("1");

    }

    else

    {

      printf("2");

    }

  
  

  return 0;

  }

• Test Case 1

  
  Input (stdin)

  2 3 4 5 6
  
  

  Expected Output

  1

• Test Case 2

  
  Input (stdin)

  5 9 6 4 7
  
  

  Expected Output

  2