CUBE SERIES
Problem Description
Your task is to write a code to find the sum of the following series
13 + 23 + 33 + + n3
Input:
Input should contain the value of the limit n
Output:
It should print the Sum of series upto n limit
CODING ARENA::
#include<stdio.h>
#include<math.h>
int main() {
int n,i;
int sum=0;
scanf("%d",&n);
sum = pow(((n * (n + 1) ) / 2),2);
for (i =1;i<=n;i++)
{
if (i != n)
printf("%d^3 + ",i);
else
printf("%d^3=%d",i,sum);
}
return 0;
}
Test Case 1
Input (stdin)2
Expected Output
1^3 + 2^3=9
Test Case 2
Input (stdin)3
Expected Output
1^3 + 2^3 + 3^3=36
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